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Date:      Thu, 7 Jun 2007 00:36:40 +0800
From:      Zhang Weiwu <zhangweiwu@realss.com>
To:        "Eric F Crist" <mnslinky@gmail.com>
Cc:        freebsd-questions@freebsd.org
Subject:   Re: share my experience: highlight parts of a text file that matches a regular expression
Message-ID:  <20070607003640.28881437@eula>
In-Reply-To: <905f1be0706060916u19f4c5coc8eb4b60521c8095@mail.gmail.com>
References:  <1181141423.18606.91.camel@joe.realss.com> <905f1be0706060916u19f4c5coc8eb4b60521c8095@mail.gmail.com>

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=E4=BA=8E Wed, 6 Jun 2007 11:16:17 -0500
"Eric F Crist" <mnslinky@gmail.com> =E5=86=99=E9=81=93:

> That's great!  One question, how do I make it highlight the entire
> line, rather than the searched-for text?

Guess would be:
$ my_app | grep --color=3Dauto -e '.*regexp.*' -e '$'

Add '.*' before and after your regular expression

>=20
> Thanks!
>=20
> Eric Crist
>=20
>=20
> On 6/6/07, Zhang Weiwu <zhangweiwu@realss.com> wrote:
> >
> > Dear list
> >
> > I'd like to highlight part of output of one application that
> > matches a regular expression. First I thought this is simple:
> >
> > $ my_app | grep --color=3Dauto 'regexp'
> >
> > This method have a big problem that lines doesn't match regexp is
> > not displayed, in my case I want all output of my_app being
> > displayed, only the matching part highlighted.
> >
> > First I thought grep might have a parameter to output everything it
> > receive, and it seems it doesn't. And I discovered I can use '-e'
> > parameter for this purpose:
> >
> > $ my_app | grep --color=3Dauto -e 'regexp' -e '$'
> >
> > The second -e makes all line matched.
> >
> > Maybe useful for some newbies.
> > --
> > Zhang Weiwu
> > Real Softservice
> > http://www.realss.com
> > +86 592 2091112
> >
> > _______________________________________________
> > freebsd-questions@freebsd.org mailing list
> > http://lists.freebsd.org/mailman/listinfo/freebsd-questions
> > To unsubscribe, send any mail to "
> > freebsd-questions-unsubscribe@freebsd.org"
> >
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