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Message-ID: <006101c22781$e66c8010$1200a8c0@gsicomp.on.ca>
From: "Matthew Emmerton" <matt@gsicomp.on.ca>
To: <freebsd-questions@FreeBSD.ORG>,
	"Kirk Strauser" <kirk@strauser.com>
References: <003101c22768$80ddb250$0801a8c0@customfilmeffects.com><20020709200449.3fcf1ba7.fxn@retemail.es> <8765zowwmo.fsf@pooh.int>
Subject: Re: How do I repeat a command N times?
Date: Tue, 9 Jul 2002 15:50:38 -0400
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>
> At 2002-07-09T18:04:49Z, "F.Xavier Noria" <fxn@retemail.es> writes:
>
> > With a Perl one-liner:
> >
> >   $ perl -e '$n = 607; system "cmd" while $n--'
>
> Mix and match!  If you know Bash or sh much better than Perl, just use
Perl
> to feed the counter:
>
>     for i in `perl -e 'print ".\n"x10;'`; do
>         echo 'foo';
>     done
>
> Replace 'x10' with 'x607' and "echo 'foo'" with whatever complicated shell
> command you've strung together and you'll have the best of both worlds (or
> worst, depending on your POV).

I've found that sh + jot works best in my experience, and doesn't involve
any counter math and comparisons:

for i in `jot 1000`
do
  <insert command to run here>
done
--
Matt Emmerton


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