From owner-freebsd-questions@FreeBSD.ORG Thu Aug 19 12:48:28 2004 Return-Path: Delivered-To: freebsd-questions@freebsd.org Received: from mx1.FreeBSD.org (mx1.freebsd.org [216.136.204.125]) by hub.freebsd.org (Postfix) with ESMTP id D5F2E16A4CE for ; Thu, 19 Aug 2004 12:48:27 +0000 (GMT) Received: from netserver2.cyonisp.net (h-69-3-40-56.cmbrmaor.covad.net [69.3.40.56]) by mx1.FreeBSD.org (Postfix) with ESMTP id F0D8243D48 for ; Thu, 19 Aug 2004 12:48:26 +0000 (GMT) (envelope-from julesg@newebmail.com) Received: from lxs1 (pool-151-199-36-46.bos.east.verizon.net [151.199.36.46]) (authenticated (0 bits)) by netserver2.cyonisp.net (8.12.9/8.11.4) with ESMTP id i7I4DC78027382 for ; Wed, 18 Aug 2004 00:13:23 -0400 Message-ID: <006a01c485ec$466b7500$3300a8c0@verizon.net> From: "Jules Gilbert" To: Date: Thu, 19 Aug 2004 08:58:29 -0400 MIME-Version: 1.0 X-Priority: 3 X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook Express 6.00.2800.1409 X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2800.1409 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable X-Content-Filtered-By: Mailman/MimeDel 2.1.1 Subject: how do I verify how sshd is starting? X-BeenThere: freebsd-questions@freebsd.org X-Mailman-Version: 2.1.1 Precedence: list List-Id: User questions List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , X-List-Received-Date: Thu, 19 Aug 2004 12:48:28 -0000 Someone else put my FreeBSD box together. How to I determine whether sshd is starting via rc.d or by inetd? I've had to tighten down the box and the changes I've made don't seem to = have any effect, though I did a shutdown and restart. Please email me your answers -- I am in a critical situation here; and = seem to have been 'discovered' in the way no one appreciates. Also, I'd appreciate a reference to a text (on-line or the paper kind) = discussing topics such as: hosts.allow, inetd.conf, sshd.conf, you = know, the stuff I should have been learning about all along... My email is julesg@newebmail.com --jg PS: Thank you;