Date: Thu, 24 Feb 2005 03:39:09 -0800 From: Soheil Hassas Yeganeh <soheil.h.y@gmail.com> To: David Bear <David.Bear@asu.edu>, freebsd-questions@freebsd.org Subject: Re: awk print Message-ID: <4c90b772050224033921bd036b@mail.gmail.com> In-Reply-To: <20050224034132.GE3123@guinness.local.mark-and-erika.com> References: <20050223214010.GA31005@asu.edu> <20050223221926.GB69249@slackbox.xs4all.nl> <20050224023605.GD31005@asu.edu> <20050224034132.GE3123@guinness.local.mark-and-erika.com>
next in thread | previous in thread | raw e-mail | index | archive | help
You can set $[1..n] to "" and then print
find ./ -name "stuff" | awk '{ $1=""; $2=""; print}
On Wed, 23 Feb 2005 22:41:32 -0500, Mark Frank <mark@mark-and-erika.com> wrote:
> * On Wed, Feb 23, 2005 at 07:36:05PM -0700 David Bear wrote:
> > On Wed, Feb 23, 2005 at 11:19:26PM +0100, Roland Smith wrote:
> > > On Wed, Feb 23, 2005 at 02:40:10PM -0700, David Bear wrote:
> > > > I'm using awk to parse a directory listing. I was hoping there is a
> > > > way to tell awk to print from $2 - to the end of the columns
> > > > available.
> > > >
> > > > find ./ -name '*stuff' | awk '{FS="/" print $3---'}
> > >
> > > Is this what you mean?:
> > >
> > > find ./ -name '*stuff'|sed 's|\.[^/]*/[^/]*/||g'
> >
> > thanks for the advice. No, this doesn't do what I want.
> >
> > If I have a directory path /stuff/stuff/more/stuff/more/and/more
> > that is n-levels deep, I want to be able to cut off the first two
> > levels and print the from 2 to the Nth level.
>
> So how about cut?
>
> find ./ -name '*stuff'| cut -d/ -f4-
>
> Mark
>
> --
> "The fix is only temporary...unless it works." - Red Green
> _______________________________________________
> freebsd-questions@freebsd.org mailing list
> http://lists.freebsd.org/mailman/listinfo/freebsd-questions
> To unsubscribe, send any mail to "freebsd-questions-unsubscribe@freebsd.org"
>
Want to link to this message? Use this URL: <https://mail-archive.FreeBSD.org/cgi/mid.cgi?4c90b772050224033921bd036b>