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Date: Sun, 19 Jul 2009 16:32:28 -0400
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From: Glen Barber <glen.j.barber@gmail.com>
To: =?ISO-8859-1?Q?Romain_Tarti=E8re?= <romain@blogreen.org>
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Cc: stable@freebsd.org
Subject: Re: Value of $? lost in the beginning of a function.
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2009/7/19 Romain Tarti=E8re <romain@blogreen.org>:
> Hi!
>
> Simple test case:
>
> ----8<----------------------
> #!/bin/sh
> foo()
> {
> =A0echo "\$?=3D$? \$1=3D$1"
> }
> false
> foo $?
> ----8<----------------------
>
> % sh foo.sh
> $?=3D0 $1=3D1
> % zsh foo.sh
> $?=3D1 $1=3D1
> % bash foo.sh
> $?=3D1 $1=3D1
>
> As you can see, the value of $? is =AB lost =BB when FreeBSD sh enters a
> function. =A0Is this supposed to behave this way?
>

Hi.

I'm no expert at shell scripting, but my first presumption is that
since you have '#!/bin/sh' at the beginning of the script, it is
creating a new subshell, and overwriting the value.  What happens if
you replace '#!/bin/sh' with '#!/usr/local/bin/zsh' ?

--=20
Glen Barber