From owner-freebsd-net Fri Mar 30 4:45:52 2001 Delivered-To: freebsd-net@freebsd.org Received: from mss.rdc2.nsw.optushome.com.au (ha1.rdc2.nsw.optushome.com.au [203.164.2.50]) by hub.freebsd.org (Postfix) with ESMTP id E9C1337B718 for ; Fri, 30 Mar 2001 04:45:48 -0800 (PST) (envelope-from s2209866@cse.unsw.edu.au) Received: from co3038206a ([203.164.177.110]) by mss.rdc2.nsw.optushome.com.au (InterMail vM.4.01.03.20 201-229-121-120-20010223) with SMTP id <20010330124548.OWYU17266.mss.rdc2.nsw.optushome.com.au@co3038206a> for ; Fri, 30 Mar 2001 22:45:48 +1000 Reply-To: From: "Daniel Wong" To: Subject: How to find the bandwidth between two machines under freeBSD? Date: Fri, 30 Mar 2001 22:46:36 +1000 Message-ID: MIME-Version: 1.0 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: 7bit X-Priority: 3 (Normal) X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook IMO, Build 9.0.2416 (9.0.2910.0) Importance: Normal X-MimeOLE: Produced By Microsoft MimeOLE V5.50.4133.2400 Sender: owner-freebsd-net@FreeBSD.ORG Precedence: bulk X-Loop: FreeBSD.org Hi, I'm trying to find out how to get the bandwidth speed for a connection between two machines. Programmatically in the kernel. Can anyone point me in the right direction ? can it be retrieved from an interface struct ?? Cheers ==================================================== Daniel Wong To Unsubscribe: send mail to majordomo@FreeBSD.org with "unsubscribe freebsd-net" in the body of the message