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From: Daniel Larsson <Daniel.Larsson@servicefactory.com>
To: Daniel Bye <freebsd-questions@slightlystrange.org>
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Date: Sat, 03 Nov 2007 15:24:23 +0100
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Cc: FreeBSD Users Questions <freebsd-questions@freebsd.org>
Subject: Re: Determining the number of files in a directory
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On Sat, 2007-11-03 at 12:49 +0000, Daniel Bye wrote:
> On Sat, Nov 03, 2007 at 12:41:51PM +0000, Daniel Bye wrote:
> > On Sat, Nov 03, 2007 at 05:27:06AM -0700, White Hat wrote:
> > > This is probably a dumb question; however, I never let a little thing=
 like=20
> > > that bother me in the past.
> >=20
> > Heheh! You and many more, my friend, myself absolutely included!
> >=20
> > > Using FreeBSD-6.2 and Bash, how do I determine the number of files in=
 a=20
> > > given directory? I have tried all sorts of combinations using differe=
nt=20
> > > flags with the 'ls' command; however, none of them displays the numbe=
r of=20
> > > files in the directory.
> >=20
> >  $ ls | wc -l
> >=20
> > will show you how many files and directories in the current (target)
> > directory. To count just files, and exclude directories, you could try
> > something like
> >=20
> >  $ find /target/directory -type f -print | wc -l
>=20
> Except of course, that would descend into the subdirectories you're tryin=
g
> not to count... Sorry - an object lesson in not hitting send before you'v=
e
> tested what you scribbled.

$ find /target/directory -maxdepth 1 -type f -print | wc -l

should do what you want though.

>=20
> Dan
>=20

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