Date: Wed, 23 Feb 2005 19:36:05 -0700 From: David Bear <David.Bear@asu.edu> To: Roland Smith <rsmith@xs4all.nl> Cc: freebsd-questions@freebsd.org Subject: Re: awk print Message-ID: <20050224023605.GD31005@asu.edu> In-Reply-To: <20050223221926.GB69249@slackbox.xs4all.nl> References: <20050223214010.GA31005@asu.edu> <20050223221926.GB69249@slackbox.xs4all.nl>
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On Wed, Feb 23, 2005 at 11:19:26PM +0100, Roland Smith wrote:
> On Wed, Feb 23, 2005 at 02:40:10PM -0700, David Bear wrote:
> > I'm using awk to parse a directory listing. I was hoping there is a
> > way to tell awk to print from $2 - to the end of the columns
> > available.
> >
> > find ./ -name '*stuff' | awk '{FS="/" print $3---'}
>
> Is this what you mean?:
>
> find ./ -name '*stuff'|sed 's|\.[^/]*/[^/]*/||g'
thanks for the advice. No, this doesn't do what I want.
If I have a directory path /stuff/stuff/more/stuff/more/and/more
that is n-levels deep, I want to be able to cut off the first two
levels and print the from 2 to the Nth level.
>
> Roland
> --
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