Date: Tue, 7 Nov 2017 21:03:22 +0300 From: Yuri Pankov <yuripv@gmx.com> To: byrnejb@harte-lyne.ca Cc: freebsd-questions@freebsd.org Subject: Re: sed - remove nul lines from file Message-ID: <f51d6c8a-c91c-dc7c-6134-e276ec60b179@gmx.com> In-Reply-To: <c2b1ffce6933bcb8f47c856a40d29b16.squirrel@webmail.harte-lyne.ca> References: <b21bf201363c34a90ab55c4a05ff8fd7.squirrel@webmail.harte-lyne.ca> <88a59a82-2902-9f63-0a94-bd23b910e7ad@gmx.com> <c2b1ffce6933bcb8f47c856a40d29b16.squirrel@webmail.harte-lyne.ca>
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On Tue, 7 Nov 2017 13:01:12 -0500, James B Byrne Via Freebsd-questions wrote: > > On Tue, November 7, 2017 12:36, Yuri Pankov wrote: >> >> Apparently, our regex engine doesn't accept the '\x' syntax, try a bit >> more complicated, but standard way :-) >> >> sed '/[[.NUL.]]/d' >> > > sed /[[.NUL.]]/g INFILE > OUTFILE You want /d, not /g, to delete the *lines* which contain NUL symbols (that's what your subject line said). > gives the same result as > > tr < INFILE -d '\000' > OUTFILE > > sed /^[[.NUL.]]$/g INFILE > OUTFILE has no effect whatsoever. No > doubt because I am not specifying the record delimiters appropriately. > >
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