Date: Sun, 03 Aug 2008 17:06:14 +0400 From: =?windows-1251?Q?=CC=E8=F5=E0=E8=EB_=CA=E8=EF=E0?= <msnkipa@mail.ru> To: freebsd-amd64@freebsd.org Subject: Intel Q6600 CPU initialization Message-ID: <E1KPdHq-00035l-00.msnkipa-mail-ru@f41.mail.ru>
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I have got Intel Q6600 and use it under FreeBSD 7STABLE (RELENG7). My cpu works with same overclocking (instead of standart 266x9 (FSBxMultiplyer) i use 425x8). When I boot my system I have these messages on the screen (and in dmesg) Timecounter "i8254" frequency 1193182 Hz quality 0 CPU: Intel(R) Core(TM)2 Quad CPU Q6600 @ 2.40GHz (3825.23-MHz K8-class CPU) Origin = "GenuineIntel" Id = 0x6fb Stepping = 11 But it really works ONLY on 3400MHz! not 3825.23-MHz! Can somebody explain me where this value calculates? Mihail.
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