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Date:      Wed, 12 Jul 2000 20:45:36 +0530
From:      Rahul Siddharthan <rsidd@physics.iisc.ernet.in>
To:        Stephen Hovey <shovey@buffnet.net>
Cc:        Alejandro Ramirez <ales@megared.net.mx>, freebsd-questions@FreeBSD.ORG
Subject:   Re: IP Address Convertion Formula???
Message-ID:  <20000712204536.A1281@physics.iisc.ernet.in>
In-Reply-To: <Pine.BSF.4.05.10007121105200.723-100000@buffnet11.buffnet.net>; from shovey@buffnet.net on Wed, Jul 12, 2000 at 11:07:43AM -0400
References:  <00b701bfec12$21ee6020$02c134c8@megared.net.mx> <Pine.BSF.4.05.10007121105200.723-100000@buffnet11.buffnet.net>

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It's the raw base 16 representation (or base 256 depending on how
you want to look at it), and the direction is forwards --
ie, 64.19.207.19 = 64*256^3+19*256^2+207*256+19 
(you can back-translate it either by dividing by powers of 256
successively, or simply by "pinging" the long number.)

Rahul.

Stephen Hovey said on Jul 12, 2000 at 11:07:43:
> 
> I believe its the raw base 10 integer representation of the dot quad value
> - but a Im not sure in which direction the significant bytes are ordered
> (in other words, if you took the 4 numbers in the dot quad, and looked at
> them as a long 4 byte integer, each value to its own byte, but In your
> example, I dont know if you look at the integer as 19 207 19 64 - or 64 19
> 207 19)
> 
> On Wed, 12 Jul 2000, Alejandro Ramirez wrote:
> 
> > Hi All,
> > 
> >     I suppose that there is a formula to translate an address like
> > "1075040019" into 64.19.207.19, does anybody know something about it that
> > could explain to me???, or where can I see information about this.
> > 
> > Thanks in Advance
> > Ales
> > 
> > 
> > 
> > 
> > 
> > 
> > 
> > 
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> > 
> 
> 
> 
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