From owner-freebsd-current  Mon Jul  2 12:25:48 2001
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Date: Mon, 2 Jul 2001 12:25:42 -0700
From: Kris Kennaway <kris@obsecurity.org>
To: David Malone <dwmalone@maths.tcd.ie>
Cc: cjclark@alum.mit.edu, David Hill <djhill@novagate.net>,
	freebsd-current@FreeBSD.ORG
Subject: Re: syslogd and -a
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References: <20010701234125.7a7d3e3a.djhill@novagate.net> <20010701212044.Q296@blossom.cjclark.org> <20010702093842.A13480@walton.maths.tcd.ie>
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In-Reply-To: <20010702093842.A13480@walton.maths.tcd.ie>; from dwmalone@maths.tcd.ie on Mon, Jul 02, 2001 at 09:38:42AM +0100
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On Mon, Jul 02, 2001 at 09:38:42AM +0100, David Malone wrote:
> On Sun, Jul 01, 2001 at 09:20:44PM -0700, Crist J. Clark wrote:
> > Hmmm... Looks like,
> >=20
> >   # syslogd -a 192.168.1.0/29
> >=20
> > Will work and,
> >=20
> >   # syslogd -a 192.168.1.1/29
> >=20
> > Won't.
>=20
> That's the standard behaviour of a netmask, isn't it? The usual
> way to check if host h is in network/netmask n/m is to check if:
>=20
> 	(h & m =3D=3D n)
>=20
> this means that the bits of the network which are not in the mask
> must be zero.

This doesn't seem to work with IPv6.  Isn't there a libc function
which can be used to do this?

Kris

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