Date: Thu, 17 Jul 1997 16:15:48 +0200 (MET DST) From: Zahemszky Gabor <zgabor@CoDe.hu> To: freebsd-questions@freebsd.org (FreeBSD questions) Cc: andrsn@andrsn.stanford.edu, vas@vas.tomsk.su Subject: Re: sed question Message-ID: <199707171415.QAA00447@CoDe.hu> In-Reply-To: <Pine.BSF.3.96.970716162230.2655A-100000@andrsn.stanford.edu> from Annelise Anderson at "Jul 16, 97 04:25:19 pm"
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> So can awk; this awk script seems to replace newlines with spaces
> (and that's all it does):
>
> BEGIN {
> FS = "\n"
> RS = ""
> }
> {
> for ( i = 1; i <= NF ; ++i)
> printf("%s", $i " ")
> }
Well, if i'd like to write it with awk instead of sed, the next would be a
bit more compact:
BEGIN {
ORS=" "
}
/^/
or instead of the last actionless pattern, a more readable (a patternless
action):
{print}
/* awk -v ORS=" " '{print}' */
By the way: if I know well, the problem with sed is that we CAN substitute a
newline, but CANNOT print anything without it.
Gabor
--
#!/bin/ksh
Z='21N16I25C25E30, 40M30E33E25T15U!' ;IFS=' ABCDEFGHIJKLMNOPQRSTUVWXYZ ';set $Z;for i { [[ $i = ? ]]&&print $i&&break;[[ $i = ??? ]]&&j=$i&&i=${i%?};typeset -i40 i=8#$i;print -n ${i#???};[[ "$j" = ??? ]]&&print -n "${j#??} "&&j=;typeset +i i;};IFS=' 0123456789 ';set $Z;X=;for i { [[ $i = , ]]&&i=2;[[ $i = ?? ]]||typeset -l i;X="$X $i";typeset +l i;};print "$X"
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