Date: Tue, 05 Oct 1999 18:28:20 +0100 From: Brian Somers <brian@Awfulhak.org> To: Tony Finch <fanf@demon.net> Cc: freebsd-questions@freebsd.org Subject: Re: execve and #! arguments Message-ID: <199910051728.SAA00876@hak.lan.Awfulhak.org> In-Reply-To: Your message of "Tue, 05 Oct 1999 10:53:21 BST." <E11YRHd-000ItM-00@fanf.eng.demon.net>
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> The manual page says:
>
> An interpreter file begins with a line of the form:
>
> #! interpreter [arg]
>
> When an interpreter file is execve'd, the system actually execve's the
> specified interpreter. If the optional arg is specified, it becomes the
> first argument to the interpreter, and the name of the originally
> execve'd file becomes the second argument; otherwise, the name of the
> originally execve'd file becomes the first argument. The original argu-
> ments are shifted over to become the subsequent arguments. The zeroth
> argument, normally the name of the execve'd file, is left unchanged.
>
> but FreeBSD allows more than one arg on the #! line, and as far as I
> can tell has done since before version 2.0. Other systems, including
> NetBSD, Linux, Solaris, Irix, 386BSD, and 4.3BSD-Reno, implement what
> the manual page says -- only one argument is passed from the #! line
> to the interpreter.
>
> Why the difference?
'cos FreeBSD's better :-)
> Tony.
> --
> f.a.n.finch dot@dotat.at fanf@demon.net
> Apache Software Foundation Member
--
Brian <brian@Awfulhak.org> <brian@FreeBSD.org>
<http://www.Awfulhak.org>; <brian@OpenBSD.org>
Don't _EVER_ lose your sense of humour ! <brian@FreeBSD.org.uk>
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