Date: Fri, 02 Jul 2010 19:35:01 +0400 From: Anonymous <swell.k@gmail.com> To: Aiza <aiza21@comclark.com> Cc: "questions@freebsd.org" <questions@freebsd.org> Subject: Re: Bourne .sh ? Message-ID: <86ocepx5ga.fsf@gmail.com> In-Reply-To: <4C2D2839.3040909@comclark.com> (Aiza's message of "Fri, 02 Jul 2010 07:43:53 %2B0800") References: <4C2D2839.3040909@comclark.com>
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Aiza <aiza21@comclark.com> writes:
> I have a file containing this
>
> drwxrwxr-x 14 89987 546 512 Jun 6 2009 7.2-RELEASE
> drwxrwxr-x 14 89987 546 512 Mar 23 04:59 7.3-RELEASE
> drwxrwxr-x 13 89987 546 512 Nov 23 2009 8.0-RELEASE
> drwxrwxr-x 13 89987 546 512 Jul 1 04:56 8.1-RC2
>
> I want to strip off everything to the left of the release
> version so I end up with this.
>
> 7.2-RELEASE
> 7.3-RELEASE
> 8.0-RELEASE
> 8.1-RC2
>
> How would I code to do this?
Use...
- glob expansion + echo builtin, e.g.
$ cd /path/to/blah && echo *
or
$ cd /path/to/blah && for f in *; do echo $f; done
- field splitting, e.g.
$ ls -l | while read $(while [ $((i+=1)) -le 9 ]; do echo p$i; done); do echo $p9; done
- stat(1) if you need not only filename but e.g. date
Of course you can use smth like cut/sed/awk/whatever but they'll only
make your script slower if you use them often.
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