From owner-freebsd-hackers Sun Jan 4 18:10:24 1998 Return-Path: Received: (from majordom@localhost) by hub.freebsd.org (8.8.7/8.8.7) id SAA18879 for hackers-outgoing; Sun, 4 Jan 1998 18:10:24 -0800 (PST) (envelope-from owner-freebsd-hackers@FreeBSD.ORG) Received: from alpo.whistle.com (alpo.whistle.com [207.76.204.38]) by hub.freebsd.org (8.8.7/8.8.7) with ESMTP id SAA18852 for ; Sun, 4 Jan 1998 18:10:15 -0800 (PST) (envelope-from julian@whistle.com) Received: (from daemon@localhost) by alpo.whistle.com (8.8.5/8.8.5) id SAA04215; Sun, 4 Jan 1998 18:01:59 -0800 (PST) Received: from UNKNOWN(), claiming to be "current1.whistle.com" via SMTP by alpo.whistle.com, id smtpd004211; Sun Jan 4 18:01:50 1998 Date: Sun, 4 Jan 1998 17:58:44 -0800 (PST) From: Julian Elischer To: Mike Smith cc: hackers@FreeBSD.ORG Subject: Re: Process wedge in 'inode' In-Reply-To: <199801040636.RAA00409@word.smith.net.au> Message-ID: MIME-Version: 1.0 Content-Type: TEXT/PLAIN; charset=US-ASCII Sender: owner-freebsd-hackers@FreeBSD.ORG Precedence: bulk If you can make a kernel from the same sources as that one, then doig it with -g and gdb -k newkernel /dev/mem will allow you to examine th s process structs etc. of those processes even without the -g kernel, you might be able to get somewhere if you can find teh address of 'allproc' as a start point. On Sun, 4 Jan 1998, Mike Smith wrote: > > Just simultaneously checking out two copies of the kernel source using > 'cvs co sys', I have an interesting situation: > > kingsford:~>ps axlwww > UID PID PPID CPU PRI NI VSZ RSS WCHAN STAT TT TIME COMMAND > 1000 1359 1348 1 -14 0 1356 864 inode D+ v1 0:06.84 cvs co sys > 1000 1366 160 4 -14 0 1356 812 inode D+ v2 0:06.77 cvs co sys > > Neither process is responding to signals, and neither can be killed. > The rest of the system is running as normal... > > This is -current as of 971220. > -- > \\ Sometimes you're ahead, \\ Mike Smith > \\ sometimes you're behind. \\ mike@smith.net.au > \\ The race is long, and in the \\ msmith@freebsd.org > \\ end it's only with yourself. \\ > > >