Date: Wed, 22 Jun 2005 13:48:00 +0700 (ICT) From: Olivier Nicole <on@cs.ait.ac.th> To: on@cs.ait.ac.th Cc: questions@freebsd.org Subject: Re: Using regex(3) Message-ID: <200506220648.j5M6m0XI089322@banyan.cs.ait.ac.th> In-Reply-To: <200506220411.j5M4BQ6G087888@banyan.cs.ait.ac.th> (message from Olivier Nicole on Wed, 22 Jun 2005 11:11:26 %2B0700 (ICT)) References: <200506220411.j5M4BQ6G087888@banyan.cs.ait.ac.th>
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> I must missunderstand how to use regex(3). To add a bit, running the same program on Linux gives the expected results: regexpr=a(.)c number of substrings=1 return from regexec=0 nmatch=0 p0.so=0 p0.eo=0 p1.so=0 p1.eo=0 p2.so=0 p2.eo=0 p3.so=0 p3.eo=0 return from regexec=0 nmatch=1 p0.so=0 p0.eo=3 p1.so=0 p1.eo=0 p2.so=0 p2.eo=0 p3.so=0 p3.eo=0 return from regexec=0 nmatch=2 p0.so=0 p0.eo=3 p1.so=1 p1.eo=2 p2.so=0 p2.eo=0 p3.so=0 p3.eo=0 Olivier
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