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Date: Wed, 10 Dec 2003 14:40:58 +0000
From: Jez Hancock <jez.hancock@munk.nu>
To: FreeBSD Questions List <freebsd-questions@freebsd.org>
Message-ID: <20031210144058.GA81732@users.munk.nu>
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Subject: sed from a shell script - invalid command code
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I'm trying to get the following Bourne shell script to output a list of
all users on the server with the exception of those listed in the
$ignore_users variable:

-snip-
#!/bin/sh
sed=/usr/bin/sed
passwd_file=/etc/passwd

ignore_users="root|toor|daemon|operator|bin|tty|kmem|games|news|man|smmsp|bind|uucp|xten|pop|nobody|mysql|www|sshd|ftp|cyrus"

cmd="$sed -E -e '/^(#|$ignore_users)/d' -e 's/:.*//' $passwd_file"

users=`cmd`
echo $users
-snip-

However when I run this code it returns:

sed: 1: "'/^(#|root|toor|daemon| ...": invalid command code '

How can I get this code to work?

If I echo out the contents of $cmd it looks as it should do:

/usr/bin/sed -E -e '/^(#|root|toor|daemon|operator|bin|tty|kmem|games|news|man|smmsp|bind|uucp|xten|pop|nobody|mysql|www|sshd|ftp|cyrus)/d' -e 's/:.*//' /etc/passwd

and if I execute that command I get the desired result - I'm just having
trouble getting the results of the command into a variable.

TIA

-- 
Jez Hancock
 - System Administrator / PHP Developer

http://munk.nu/
http://jez.hancock-family.com/