From owner-freebsd-questions Tue May 8 23:23: 1 2001 Delivered-To: freebsd-questions@freebsd.org Received: from thccx9.oz.nthu.edu.tw (thccx9.Oz.nthu.edu.tw [140.114.63.51]) by hub.freebsd.org (Postfix) with ESMTP id 3D90C37B422 for ; Tue, 8 May 2001 23:22:57 -0700 (PDT) (envelope-from u881504@oz.nthu.edu.tw) Received: from 2kftyrnk28jasgw (u881504.LI.ab.nthu.edu.tw [140.114.221.136]) by thccx9.oz.nthu.edu.tw (Postfix) with SMTP id CA0DD6BD9F for ; Wed, 9 May 2001 14:22:49 +0800 (CST) Message-ID: <000801c0d851$595fe020$88dd728c@2kftyrnk28jasgw> From: =?big5?B?s6+tq7PN?= To: Subject: Please solve a problem for me Date: Wed, 9 May 2001 14:29:06 +0800 MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="----=_NextPart_000_0005_01C0D894.6759C630" X-Priority: 3 X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook Express 5.00.2919.6700 X-MimeOLE: Produced By Microsoft MimeOLE V5.00.2919.6700 Sender: owner-freebsd-questions@FreeBSD.ORG Precedence: bulk X-Loop: FreeBSD.ORG This is a multi-part message in MIME format. ------=_NextPart_000_0005_01C0D894.6759C630 Content-Type: text/plain; charset="big5" Content-Transfer-Encoding: quoted-printable Hello: Can you solve a problem for me? That is when I use the "telnet" = method like "telnet 140.114.63.13" at command line.The screen doesn't do anything ,and it even doesn't display any wrong message.But I can use method like "ping","ftp" etc..(it shoud respect my network setting = is correct).The version I use is "FreeBSD 4.2 Release".Thank you for solving problem for me. = aoldman ------=_NextPart_000_0005_01C0D894.6759C630 Content-Type: text/html; charset="big5" Content-Transfer-Encoding: quoted-printable

Hello:

Can you solve a problem for me? That is = when I=20 use the "telnet" method like "telnet 140.114.63.13" at command=20 line.The screen doesn't

do anything ,and it = even=20 doesn't display any wrong message.But I can

use method like "ping","ftp" etc..(it shoud respect = my network=20 setting is

correct).The version I use is "FreeBSD 4.2 = Release".Thank=20 you

for solving problem for me.

&nbs= p; = ; = &= nbsp; &n= bsp; &nb= sp; &nbs= p;=20 aoldman

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