Date: Fri, 21 May 1999 12:00:39 +0300 From: Ruslan Ermilov <ru@ucb.crimea.ua> To: Yusuf Goolamabbas <yusufg@outblaze.com> Cc: freebsd-stable@FreeBSD.ORG Subject: Re: Trying to understand "proc: table is full" message Message-ID: <19990521120039.A10590@relay.ucb.crimea.ua> In-Reply-To: <19990521061520.29924.qmail@yusufg.portal2.com>; from Yusuf Goolamabbas on Fri, May 21, 1999 at 06:15:20AM -0000 References: <19990521061520.29924.qmail@yusufg.portal2.com>
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On Fri, May 21, 1999 at 06:15:20AM -0000, Yusuf Goolamabbas wrote:
> Hi, I have a PII-333 box with 196MB of RAM and two SCSI disks
> (4GB,8GB) connected to an Adaptec 7880 card. I am running 3.2-STABLE
> cvsupped yesterday and have configured kernel with maxusers 64 and
> nmbclusters 4096. Also, I have set somaxconn to be 256
>
> This machine gets a decent volume of mail and also gets a good traffic
> of web hits to sites which run a lot of CGI programs
>
> I started to see this messages since yesterday
> /kernel: proc: table is full
>
> on the console and in /var/log/messages
>
> Would appreciate if someone could provide pointers on how to interpret
> this message and what parameters I should be tweaking. I am
> considering upgrading the box to 512MB of RAM
>
> Thanks, Yusuf
You need to bounce MAXUSERS.
From the /usr/src/sys/kern/kern_fork.c:
% /*
% * Although process entries are dynamically created, we still keep
% * a global limit on the maximum number we will create. Don't allow
% * a nonprivileged user to use the last process; don't let root
% * exceed the limit. The variable nprocs is the current number of
% * processes, maxproc is the limit.
% */
% uid = p1->p_cred->p_ruid;
% if ((nprocs >= maxproc - 1 && uid != 0) || nprocs >= maxproc) {
% tablefull("proc");
% return (EAGAIN);
% }
The formula for ``maxproc'' is ``maxproc = 20 + 16 * MAXUSERS'',
and is hardcoded in /usr/src/sys/conf/param.c.
--
Ruslan Ermilov Sysadmin and DBA of the
ru@ucb.crimea.ua United Commercial Bank
+380.652.247.647 Simferopol, Ukraine
http://www.FreeBSD.org The Power To Serve
http://www.oracle.com Enabling The Information Age
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