Date: Wed, 6 Jun 2012 19:19:01 -1000 From: Parv <parv@pair.com> To: Tim Daneliuk <tundra@tundraware.com> Cc: FreeBSD Mailing List <freebsd-questions@freebsd.org> Subject: Re: Somewhat OT - A Makefile Question Message-ID: <20120607051901.GA2205@holstein.holy.cow> In-Reply-To: <4FCF48AF.307@tundraware.com> References: <4FCF48AF.307@tundraware.com>
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in message <4FCF48AF.307@tundraware.com>,
wrote Tim Daneliuk thusly...
>
...
> Within a makefile, I need to assign the name of a program as in:
>
> FOO = "bar".
>
> The problem is that 'bar' may also be know as, say, "bar.sh".
...
> Is there a simple way to determine which form "bar" or "bar.sh" on
> on a given system *at the time the make is run*? If both exist, I
> will pick one arbitrarily,
...
> For example I don't think this works when both are there:
>
> FOO = $(shell `which bar bar.sh)
Modify the subshell command to ...
which bar bar.sh | head -n 1
... as in (for FreeBSD make) ...
shell=`which zsh sh tcsh csh 2>/dev/null | fgrep -v 'not found' | head -n 3`
all:
@printf "%s\n" ${shell}
- parv
--
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