Date: Tue, 27 May 2003 19:20:06 +1000 From: Peter Jeremy <peterjeremy@optushome.com.au> To: Doug Rabson <dfr@nlsystems.com> Cc: freebsd-hackers@freebsd.org Subject: Re: x86-64 support Message-ID: <20030527092006.GB44520@cirb503493.alcatel.com.au> In-Reply-To: <200305270956.58065.dfr@nlsystems.com> References: <200304280054.h3S0sTi2006266@lurza.secnetix.de> <200305270956.58065.dfr@nlsystems.com>
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On Tue, May 27, 2003 at 09:56:58AM +0100, Doug Rabson wrote:
>On Monday 28 April 2003 1:54 am, Oliver Fromme wrote:
>> You don't need that; the digits of pi can be calculated
>> quite easily with integer math. This snippet is from my
>> signature collection:
>>
>> int f[9800],b,c=9814,g,i;long
>> a=1e4,d,e,h;main(){for(;b=c,c-=14;i=printf(
>> "%04d",e+d/a),e=d%a)while(g=--b*2)d=h*b+a*(i?f[b]:a/5),h=d/--g,f[b]=d
>>%g;}
>>
>> Of course it doesn't comply with style(9), otherwise it
>> wouldn't fit into two lines. Prettifying (de-obfuscating)
>> it to make it style(9)-compliant is left as an exercise to
>> the reader. ;-)
>
>Doesn't appear to work. When I run this, it prints '1877' followed by
>lots of zeros...
A followup pointed out that there is an error in the size of 'f': it
should be f[9814] (matching c). With this change, the result looks
reasonably close to pi.
Peter
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