Date: Sun, 12 Mar 1995 03:57:53 -0800 From: hasty@netcom.com (Amancio Hasty Jr) To: bde@zeta.org.au, hackers@FreeBSD.org, hasty@netcom.com Subject: Re: text's start address? Message-ID: <199503121157.DAA18737@netcom14.netcom.com>
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This is what I am doing:
gcc -Xlinker "-Z" static -o mdos.mon test.c
here is a hexdump of mdos.mon:
0000000 010b 0000 9000 0000 2000 0000 2544 0000
0000010 102c 0000 0018 0000 0000 0000 0000 0000
0000020 0000 0000 0000 0000 0000 0000 0000 0000
*
------
(mdos reads header of mdos.mon)
gdb mdos
...
Breakpoint 1, main (argc=1, argv=0xefbfd978) at mdos.c:176
176 asm volatile("movl %1, %%esp; jmp %2" :
(gdb) print ex
$3 = {a_magic = 267, a_text = 36864, a_data = 8192, a_bss = 9540,
a_syms = 4140, a_entry = 24, a_trsize = 0, a_drsize = 0}
a_entry appears to have a low value
/bg/local/src/mdos/src/monitor > gdb mdos.mon
GDB is free software and you are welcome to distribute copies of it
under certain conditions; type "show copying" to see the conditions.
There is absolutely no warranty for GDB; type "show warranty" for details.
GDB 4.13 (i386-unknown-freebsd),
Copyright 1994 Free Software Foundation, Inc...
(gdb) x/i main
0x578 <main>: pushl %ebp
So it appears that for me to get to main the actual address is
0x1578. Now the question is how can I arrive at this number
from the data structure ex?
Tnks
Amancio
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