Date: Sun, 11 Jan 2009 19:14:29 -0800 From: George Davidovich <freebsd@optimis.net> To: freebsd-questions@freebsd.org Subject: Re: bash versus sh test builtin Message-ID: <20090112031429.GA42596@marvin.optimis.net> In-Reply-To: <7740275E-77AA-45C1-B95E-C1F62D2AAB29@goldmark.org> References: <7740275E-77AA-45C1-B95E-C1F62D2AAB29@goldmark.org>
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On Sun, Jan 11, 2009 at 08:08:18PM -0600, Jeffrey Goldberg wrote: > The -ne operator for [ in /bin/sh doesn't seem to work as in bash. > Also the bash behavior here is what matches /bin/[ most closely. > > $ /bin/sh > $ if [ $UID -ne 0 ] ; then > > echo not root > > fi > [: -ne: unexpected operator > $ exit > $ echo $SHELL > /usr/local/bin/bash > [jeffrey@dobby ~/src/mount-rsnap]$ if [ $UID -ne 0 ] ; then > > echo not root > > fi > not root > > Does anyone have a recommendation of how to run this simple test in / > bin/sh if [ $(id -u) -ne 0 ]; then ... As to why your test isn't working as expected, rewrite your script to read: #!/bin/sh echo $UID and you'll discover that UID is a bash environmental variable. > and how to write tests reasonably portably? That's a different question, and merits a much longer discussion probably better had elsewhere. I'd suggest comp.unix.shell. -- George
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