Date: Wed, 10 Jun 2015 14:02:06 -0700 From: Craig Rodrigues <rodrigc@FreeBSD.org> To: Robert Simmons <rsimmons0@gmail.com> Cc: freebsd-python@freebsd.org Subject: Re: Python Subprocess Crontab Problem Message-ID: <CAG=rPVdkzy%2BK1KV2AP4O-j-4UqoPz5pLrQX7u9NJkEuuqQ5eqA@mail.gmail.com> In-Reply-To: <CA%2BQLa9BjC=M-5wxA0gzoTJO1xHL9XbhpTN10QhhrdCG9bxf3Lg@mail.gmail.com> References: <CA%2BQLa9BjC=M-5wxA0gzoTJO1xHL9XbhpTN10QhhrdCG9bxf3Lg@mail.gmail.com>
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On Wed, Jun 10
> Here is how I'm calling the script in crontab:
> PATH=$PATH:/usr/local/bin
>
I can't remember offhand, but I don't think you can do that.
I think you may need to fully specify the PATH instead of using $PATH.
> errors = open('/home/myuser/error', 'wb')
>
> with tempfile.TemporaryDirectory() as tmpdirname:
> tempthing = os.path.join(tmpdirname, thing)
> fh = open(tempthing, 'wb')
> fh.write(b'123')
> fh.close()
> zipname = '{}.zip'.format(thing)
> ziptempfile = os.path.join(tmpdirname, zipname)
>
Can you add right here:
print("PATH: %s" % os.environ['PATH'], file=errors)
and see what the PATH is in your errors file?
--
Craig
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