Date: Sun, 30 Nov 2008 18:19:11 +0000 From: Matthew Seaman <m.seaman@infracaninophile.co.uk> To: Drew Tomlinson <drew@mykitchentable.net> Cc: FreeBSD Questions <freebsd-questions@freebsd.org> Subject: Re: Regular Expression Help Message-ID: <4932D91F.5040804@infracaninophile.co.uk> In-Reply-To: <4932CA0D.8080109@mykitchentable.net> References: <4932CA0D.8080109@mykitchentable.net>
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Drew Tomlinson wrote:
> I'm attempting to take an ldiff file and flip first/last name order. =20
> However I can not figure out how to match hyphenated last names. In=20
> vim, my current search/replace string is:
>=20
> %s/cn=3D\(\w\+\-*\) \(\w\+\),/cn=3D\2 \1,/gc
>=20
> This will match:
>=20
> cn=3DSmith Joe,
>=20
> and replace it with:
>=20
> cn=3DJoe Smith,
>=20
> But it will not match:
>=20
> cn=3DSmith-Brown Joe,
>=20
> nor replace it with:
>=20
> cn=3DJoe Smith-Brown,
>=20
> I've tried various incantations of escaping and quantifying yet I can=20
> not figure out how to do what I want.
Well, assuming that none of the surnames contain ',' and that the first '=
'
(space) is always the delimiter between the surname and that anything els=
e
is forenames ...=20
% cat foo.txt=20
cn=3DSmith Joe,
cn=3DSmith-Brown Joe,
% perl -p -e 's/cn=3D([^ ,]+) ([^,]+),/cn=3D$2 $1,/' < foo.txt=20
cn=3DJoe Smith,
cn=3DJoe Smith-Brown,
ie. you need a s/// command that understands negated character classes. =
I
think sed(1) and vi(1) will do that, but I haven't time to look up the pr=
ecise
syntax. Perl, of course, just does the job for me.
Cheers,
Matthew
--=20
Dr Matthew J Seaman MA, D.Phil. 7 Priory Courtyard
Flat 3
PGP: http://www.infracaninophile.co.uk/pgpkey Ramsgate
Kent, CT11 9PW
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