Date: Wed, 27 Jul 2005 20:34:13 -0400 From: Garance A Drosihn <drosih@rpi.edu> To: martin@orbweavers.co.uk, freebsd-questions@freebsd.org Subject: Re: Shell script frustration Message-ID: <p06230909bf0dd7e0e787@[128.113.24.47]> In-Reply-To: <1559.192.168.0.10.1122502486.squirrel@192.168.0.5> References: <1559.192.168.0.10.1122502486.squirrel@192.168.0.5>
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At 11:14 PM +0100 7/27/05, martin@orbweavers.co.uk wrote:
>
>echo ldapdelete -W -D $binddn \"cn=$1, $group_base\"
>ldapdelete -W -D $binddn \"cn=$1, $group_base\"
>when run ('./rmgroup users') it outputs -
>
>ldapdelete -W -D "cn=Manager,dc=orbweavers,dc=co,dc=uk" "cn=users,
>ou=groups,dc=orbweavers,dc=co,dc=uk"
>Enter LDAP Password:
>ldap_bind: Invalid DN syntax (34)
> additional info: invalid DN
>
>However, if I copy and paste the echod statement (the first line
>of the output) straight to the shell, it run fine.
What I do in this cases is create a script called "list_args.sh":
#!/bin/sh
printf "\nlist_args.sh at `date +%H:%M:%S` with \$# = $#\n"
# Process all parameters.
N=0
while test $# != 0 ; do
N=$(($N+1))
printf " \$$N = [%3d] '$1'\n" ${#1}
shift
done
Then in your script, replace the ldapdelete command with
list_args.sh. That way you'll see *exactly* what ldapdelete
is seeing for parameters, and that might help.
--
Garance Alistair Drosehn = gad@gilead.netel.rpi.edu
Senior Systems Programmer or gad@freebsd.org
Rensselaer Polytechnic Institute or drosih@rpi.edu
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