Date: Thu, 25 Dec 2003 00:47:08 +0100 From: "Daan Vreeken [PA4DAN]" <Danovitsch@Vitsch.net> To: "gffds fsdff" <eurijk666@hotmail.com> Cc: FreeBSD-questions@FreeBSD.org Subject: Re: The Booting Process Message-ID: <200312250047.08843.Danovitsch@Vitsch.net> In-Reply-To: <BAY7-F30gCT49PXcdKE000152fc@hotmail.com> References: <BAY7-F30gCT49PXcdKE000152fc@hotmail.com>
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On Thursday 25 December 2003 00:25, gffds fsdff wrote:
> Is there a way, when booting, to have an application launch?
> Ex:
> exec /usr/servers/bots/zDSBot3/zDSBot3 &
Have a look at /usr/local/etc/rc.d
All scripts that are executable and end in ".sh" in that directory get=20
executed at boot-time. You could create your own scripts in that director=
y=20
that starts your application.
On boot the scripts are executed with the first agrument being "start". O=
n=20
shutdown the scripts are executed with "stop" as first argument. By check=
ing=20
the argument in your script you can determine if you should start the=20
application or not. (Don't start it at shutdown :)
A simple rc.d-script could look something like this :
--- cut here ---
#!/bin/sh
case "$1" in
start)
=09/some/dir/some-app && echo -n ' some-app'
;;
stop)
;;
*)
echo "Usage: `basename $0` {start|stop}" >&2
;;
esac
exit 0
--- cut here ---
The "echo -n" line is the output you see when you boot your system after =
:
"Local package initialization :"
This only works on applications that daemonize (dissapear into the backgr=
ound=20
when you start them). If your program doesn't daemonize, you should start=
it=20
with an "&" sign behind it...
grtz,
Daan
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