Date: Thu, 9 Dec 1999 10:49:30 -0500 (EST) From: "Crist J. Clark" <cjc@cc942873-a.ewndsr1.nj.home.com> To: jconner@enterit.com (Jim Conner) Cc: freebsd-questions@FreeBSD.ORG (FreeBSD Questions) Subject: Re: hopefully three simple questions Message-ID: <199912091549.KAA60420@cc942873-a.ewndsr1.nj.home.com> In-Reply-To: <4.2.0.58.19991208084058.009ac100@mail.enterit.com> from Jim Conner at "Dec 8, 1999 08:44:50 am"
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Jim Conner wrote,
> I sent these to Crist last night. The shell script doesn't work :) (what
> can I say...I threw it together in 20 minutes)....however, the find will at
> least give a count of files in each directory based on where you run the
> find command from and store the output to a file of your choice. I don't
> think you will be able to answer this guy's questions with simple command
> on the command line. Its going to require scripting (I think)
>
> find . -type d -exec wc -l {} \; >files.out
I don't see how that would work. You are using wc(1) on the diretory,
which in this context is a binary file with some info in it. It
does not give the right answer,
% ls -a /
. boot.help kernel.GENERIC share usr2
.. c kernel.config stand usr3
.cshrc cdrom kernel.old sys usr4
.profile compat mnt tmp var
COPYRIGHT dev modules u1
bin etc proc u2
boot home root users
boot.config kernel sbin usr
% ls -a / | wc -l
36
% wc -l /
4 /
> #!/bin/ksh
>
> counter=0
> var=0
> file=files.out
> find . -type d -exec wc -l {} \; >$file
>
> for loop in `cat $file | grep -E [0-9] | awk '{print $1}'`
> do
> counter=$((counter + 1))
> var[$counter]=$loop
> if [ $counter = 2 ]
> then
> if [ ${var[1]} -gt ${var[2]} ]
> then
> largest=${var[1]}
> counter=1
> elif [ ${var[2]} -gt ${var[1]} ]
> then
> largest=${var[2]}
> counter=1
> else
> counter=1
> fi
> else
> blah=0
> fi
> done
> echo "The largest directory had $largest files: `grep $largest $file`"
> rm $file
I think the best way to do this would be a recursive shell script,
#!/bin/sh
#
# dirmax - cjc, 1999/12/09
#
# usage: dirmax [dir]
#
# Returns the maximum depth and number of members in
# the directory with the most members on stdout. If
# no argument is give, the pwd is used.
# This function takes the following args,
# usage: dirstats dir depth maxdepth
dirstats () {
cd $1
MAXNUM=`ls -A | wc -l`
MAXDEPTH=0
for DIR in `ls -A`; do
if [ -d $DIR ]; then
set -- `dirstats $DIR $MAXDEPTH`
if [ $1 -gt $MAXDEPTH ]; then
MAXDEPTH=$1
fi
if [ $2 -gt $MAXNUM ]; then
MAXNUM=$2
fi
fi
done
MAXDEPTH=`expr $MAXDEPTH + 1`
echo $MAXDEPTH $MAXNUM
}
if [ $# -gt 1 ]; then
echo "$0: usage: dirmax [dir]" >&2
elif [ $# -eq 0 ]; then
STARTDIR=.
else
STARTDIR=$1
fi
dirstats $STARTDIR 0
exit 0
Fair warning: There are no checks for symbolic links making infinte
loops, handling of directories without read permissions, etc.
--
Crist J. Clark cjclark@home.com
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