Date: Tue, 30 Apr 2002 11:11:38 -0700 (PDT) From: Francis Jordan <francrj@yahoo.com> To: Dag-Erling Smorgrav <des@ofug.org> Cc: freebsd-chat@freebsd.org Subject: Re: strange gcc warning Message-ID: <20020430181138.37192.qmail@web20403.mail.yahoo.com> In-Reply-To: <xzpheltrxp5.fsf@flood.ping.uio.no>
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Hi Dag-Erling,
The warning goes away when I wrap the array in a
struct, but I still don't understand it clearly.
If the array is converted to a pointer, isn't it
safe to cast a regular pointer to a pointer to
const (i.e. a read-only pointer)?
If I write:
void foo(const int *p) {}
int main()
{
int *i = 0;
foo(i);
return 0;
}
there is no warning.
Thanks
FRJ
--- Dag-Erling Smorgrav <des@ofug.org> wrote:
> Francis Jordan <francrj@yahoo.com> writes:
> > This may seem like a newbie question, but still --
> why
> > does the following produce a warning:
> >
> > void
> > foo(const int b[8][8])
> > {
> > }
>
> Arrays degenerate to pointers when passed as
> arguments to functions.
> You can wrap it in a struct if you want to keep the
> size information;
> otherwise foo() will have to do the necessary
> pointer arithmetic "by
> hand".
>
> DES
> --
> Dag-Erling Smorgrav - des@ofug.org
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