Date: Wed, 29 May 2002 21:59:47 -0500 From: Stephen Montgomery-Smith <stephen@math.missouri.edu> To: freebsd-questions@FreeBSD.ORG Subject: Re: Measuring throughput of network Message-ID: <3CF595A3.1B8B0F48@math.missouri.edu> References: <3CF5921C.34EE1888@math.missouri.edu> <20020530024829.GD78068@dan.emsphone.com>
next in thread | previous in thread | raw e-mail | index | archive | help
Dan Nelson wrote:
>
>
> netstat -ib. Note that all the numbers wrap at 4gb, so if you're
> planning on graphing the values, you'll need to make sure your poll
> period is less than 1/2 your wrap period.
>
Thanks for the fast answer. So I typed
netstat -I rl0 -b
and got the answer
Name Mtu Network Address Ipkts Ierrs Ibytes Opkts Oerrs Obytes Coll
rl0 1500 <Link#1> 00:50:ba:d3:a8:0a 1460837 0 213986862 348799 0 140996485 0
rl0 1500 fe80:1::250 fe80:1::250:baff: 0 - 0 0 - 0 -
rl0 1500 12-216-240-0. home 89752 - 24681411 348729 - 136111101 -
Now I am wondering which one actually represents my true throughput. I am guessing that the first answer includes the many "arp who-has"s that I keep getting on my @home connection. Would it be true to say that it is the third line that represents the true throughput? ("home" is the name of my computer.)
--
Stephen Montgomery-Smith
stephen@math.missouri.edu
http://www.math.missouri.edu/~stephen
To Unsubscribe: send mail to majordomo@FreeBSD.org
with "unsubscribe freebsd-questions" in the body of the message
Want to link to this message? Use this URL: <https://mail-archive.FreeBSD.org/cgi/mid.cgi?3CF595A3.1B8B0F48>