From owner-freebsd-questions@FreeBSD.ORG Fri Feb 13 02:48:47 2009 Return-Path: Delivered-To: freebsd-questions@freebsd.org Received: from mx1.freebsd.org (mx1.freebsd.org [IPv6:2001:4f8:fff6::34]) by hub.freebsd.org (Postfix) with ESMTP id 63C37106564A for ; Fri, 13 Feb 2009 02:48:47 +0000 (UTC) (envelope-from jalmberg@identry.com) Received: from mx1.identry.com (on.identry.com [66.111.0.194]) by mx1.freebsd.org (Postfix) with ESMTP id 009CF8FC16 for ; Fri, 13 Feb 2009 02:48:46 +0000 (UTC) (envelope-from jalmberg@identry.com) Received: (qmail 81099 invoked by uid 89); 13 Feb 2009 02:49:14 -0000 Received: from unknown (HELO ?192.168.1.110?) (jalmberg@75.127.142.66) by mx1.identry.com with ESMTPA; 13 Feb 2009 02:49:14 -0000 In-Reply-To: <9391FD2D-59ED-455A-8C87-2854C7EF1E52@mac.com> References: <325E4EC8-BD2B-45C1-978C-4922D16D3A94@identry.com> <9391FD2D-59ED-455A-8C87-2854C7EF1E52@mac.com> Mime-Version: 1.0 (Apple Message framework v753.1) Content-Type: text/plain; charset=US-ASCII; delsp=yes; format=flowed Message-Id: Content-Transfer-Encoding: 7bit From: John Almberg Date: Thu, 12 Feb 2009 21:48:44 -0500 To: Chuck Swiger X-Mailer: Apple Mail (2.753.1) Cc: freebsd-questions@freebsd.org Subject: Re: Old user can't log in X-BeenThere: freebsd-questions@freebsd.org X-Mailman-Version: 2.1.5 Precedence: list List-Id: User questions List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , X-List-Received-Date: Fri, 13 Feb 2009 02:48:47 -0000 On Feb 12, 2009, at 7:19 PM, Chuck Swiger wrote: > On Feb 12, 2009, at 3:14 PM, John Almberg wrote: >> Just ran into a strange problem... I have a long-standing user >> account on my FreeBSD box that no longer works. She can't ssh into >> the box, and I can't even su to her account. >> >> $ su jessica >> Password: >> su: setusercontext: Invalid argument > > Does group 1022 exist in /etc/groups? Yes > Is the user a member of more than 16 groups? Actually, 15 plus it's own group, so yes, I guess exactly 16. I can guess what you're going to say next. Frack... Okay, I guess I can reorganize groups to eliminate this problem. Thanks for the hint (as they say, a hint to the wise is sufficient...) -- John