Date: Thu, 20 Oct 2005 15:17:17 +0200 From: Emanuel Strobl <Emanuel.strobl@gmx.net> To: freebsd-questions@freebsd.org Subject: (bourne)shell variable names containing a variable? Message-ID: <200510201517.34489@harrymail>
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Hello,
I try to assign a value to a variable, but the variable should consist of=20
another variable. Is this possible (in bourne shell)?
Example:
#!/bin/sh
list=3D"one two three four"
for item in $list; do
${item}_present=3Dyes
done
This doesn't work since the shell tries to execute "one_present=3Dyes"=20
instead of assigning yes to one_present....
What am I missing????
Thanks a lot,
=2DHarry
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