Date: Mon, 7 Dec 1998 12:16:45 -0800 (PST) From: z@rentaboat.se To: freebsd-gnats-submit@FreeBSD.ORG Subject: misc/8998: Problem with alarm(3) Message-ID: <199812072016.MAA10740@hub.freebsd.org>
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>Number: 8998
>Category: misc
>Synopsis: Problem with alarm(3)
>Confidential: no
>Severity: non-critical
>Priority: low
>Responsible: freebsd-bugs
>State: open
>Quarter:
>Keywords:
>Date-Required:
>Class: sw-bug
>Submitter-Id: current-users
>Arrival-Date: Mon Dec 7 12:20:00 PST 1998
>Last-Modified:
>Originator: Zs
>Organization:
>Release: FreeBSD 2.2.7
>Environment:
FreeBSD <fqdn> 2.2.7-RELEASE FreeBSD 2.2.7-RELEASE #0: Wed Oct 21 15:42:
16 GMT 1998 z@<fqdn>:/usr/src/sys/compile/<HOSTNAME>-KERN i386
>Description:
The manual for alarm(3) states that the maximum number of seconds
allowed is 2147483647, but alarm() calls setitimer() which accepts
only 100000000 seconds.
>How-To-Repeat:
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
int
main(void)
{
(void) alarm(100000001);
if (sleep(1) != 0) {
(void) fprintf(stderr, "Sleep got interrupted\n");
return EXIT_FAILURE;
}
(void) printf("Seconds left of the timer: %u\n", alarm(0));
return EXIT_SUCCESS;
}
>Fix:
Change the limit stated in the man page to 100000000, and in
/usr/src/lib/libc/gen/alarm.c, check if the caller has specified
a larger value and return -1 if so.
>Audit-Trail:
>Unformatted:
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