Date: Thu, 11 Aug 2005 20:04:29 -0700 (PDT) From: dpk <dpk@dpk.net> To: Xu Qiang <Qiang.Xu@fujixerox.com> Cc: Giorgos Keramidas <keramida@ceid.upatras.gr>, freebsd-questions@freebsd.org Subject: RE: Help on bash script? Message-ID: <20050811200106.S5643@shared10.hosting.flyingcroc.net> In-Reply-To: <20050812025925.942541D9A4@imss.sgp.fujixerox.com> References: <20050812025925.942541D9A4@imss.sgp.fujixerox.com>
next in thread | previous in thread | raw e-mail | index | archive | help
On Fri, 12 Aug 2005, Xu Qiang wrote: > This is my test script: > > --------------------- > #!/bin/bash > > var=0 > var=$[3] > > vari=0 > ++vari > > echo $var > echo $vari > --------------------- > > The result is: > ./test.sh: ++vari: command not found > 3 > 0 > > So the manual of bash is incorrect? > > Regards, > Xu Qiang It will work with either 'let' or within an 'arithmetic expansion': $[++var] let ++var By the way, there is another syntax, from the man page, that seems to operate identically: $((++var)) and $((var+1))
Want to link to this message? Use this URL: <https://mail-archive.FreeBSD.org/cgi/mid.cgi?20050811200106.S5643>