From owner-freebsd-bugs  Thu Jun  3 20:10: 5 1999
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Date: Thu, 3 Jun 1999 20:10:02 -0700 (PDT)
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To: freebsd-bugs@FreeBSD.org
Cc: 
From: "Kenneth D. Merry" <ken@plutotech.com>
Subject: Re: kern/12017: no quirk for Nakamichi cd changer
Reply-To: "Kenneth D. Merry" <ken@plutotech.com>
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The following reply was made to PR kern/12017; it has been noted by GNATS.

From: "Kenneth D. Merry" <ken@plutotech.com>
To: archon@forbidden.dough.net
Cc: FreeBSD-gnats-submit@FreeBSD.ORG
Subject: Re: kern/12017: no quirk for Nakamichi cd changer
Date: Thu, 3 Jun 1999 21:00:42 -0600 (MDT)

 archon@forbidden.dough.net wrote...
 > 
 > >Number:         12017
 > >Category:       kern
 > >Synopsis:       no quirk for Nakamichi cd changer
 > >Confidential:   no
 > >Severity:       non-critical
 > >Priority:       medium
 > >Responsible:    freebsd-bugs
 > >State:          open
 > >Quarter:        
 > >Keywords:       
 > >Date-Required:
 > >Class:          change-request
 > >Submitter-Id:   current-users
 > >Arrival-Date:   Thu Jun  3 18:40:00 PDT 1999
 > >Closed-Date:
 > >Last-Modified:
 > >Originator:     Dennis Moore
 > >Release:        FreeBSD 3.2-RELEASE i386
 > >Organization:
 > Forbidden DoughNet Enterprises
 > >Environment:
 > 
 > cd1: <NAKAMICH MJ-5.16S 1.07> Removable CD-ROM SCSI-2 device 
 > cd1: 10.000MB/s transfers (10.000MHz, offset 15)
 > cd1: cd present [302895 x 2048 byte records]
 > 
 > 
 > >Description:
 > 
 > No quirk for this cd-changer device.
 > http://www.nakamichi.com/computer/mj5_16spec.htm
 
 You shouldn't need a quirk entry, as the comment above the quirk table
 says:
 
 /*      
  * These quirk entries aren't strictly necessary.  Basically, what they do
  * is tell cdregister() up front that a device is a changer.  Otherwise, it
  * will figure that fact out once it sees a LUN on the device that is
  * greater than 0.  If it is known up front that a device is a changer, all
  * I/O to the device will go through the changer scheduling routines, as
  * opposed to the "normal" CD code.
  */     
 
 Does your drive function properly without the quirk entry?
 
 Ken
 -- 
 Kenneth Merry
 ken@plutotech.com
 


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