Date: Sun, 10 Apr 2005 14:04:23 +0200 From: Dimitry Andric <dimitry@andric.com> To: Daniel Ellard <ellard@eecs.harvard.edu> Cc: freebsd-current@freebsd.org Subject: Re: smbfs bug introduced at smbfs_vnops.c:1.58 Message-ID: <1892195662.20050410140423@andric.com> In-Reply-To: <20050410074009.N66651@bowser.eecs.harvard.edu> References: <200504100251.j3A2pLEH055107@sana.init-main.com> <20050410092417.GA774@galgenberg.net> <20050410074009.N66651@bowser.eecs.harvard.edu>
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------------1291C69219E9F339 Content-Type: text/plain; charset=us-ascii Content-Transfer-Encoding: 7bit On 2005-04-10 at 13:45:50 Daniel Ellard wrote: >> int main(void) { >> int a; >> a+=1; >> return (0); >> } [snip] > If you change the -O to -g, then the code for "a" is not > removed -- but there's still no warning. I think this is > a bug, because if the expression wasn't an innocuous a+=1 > it could be a real problem if the variable wasn't removed. The idea here is that gcc sees that the value of a is never used, and therefore it doesn't have to warn. (Whether you agree with this, or not, is more of a political or philosophical question. ;) But as soon as you actually *do* something with a's value afterwards, it will start to complain. IOW, if you change main into: int main(void) { int a; a += 1; a++; //...bunch of other operations on a... ++a; a *= 3; return 0; } and gcc will still issue no warning. However, add one actual *use* of a: extern void f(int i); int main(void) { int a; a += 1; f(a); return 0; } and you'll get the warning you want... :) ------------1291C69219E9F339 Content-Type: application/pgp-signature -----BEGIN PGP MESSAGE----- Version: GnuPG v1.4.0 (MingW32) iD8DBQFCWRZHsF6jCi4glqMRAlQwAKCcHtIlJkcR3rdp2N99qz6JimAGLwCcDisx Xiqm/Q0yy9TeULi2QHQnwts= =hO98 -----END PGP MESSAGE----- ------------1291C69219E9F339--
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