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From: "Charles Howse" <chowse@charter.net>
To: "'Rob Lahaye'" <lahaye@snu.ac.kr>,
	"'Gil Agno Virtucio'" <gihl@nesic.com.ph>,
	<freebsd-questions@FreeBSD.ORG>
Date: Thu, 18 Sep 2003 05:59:57 -0500
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Subject: RE: randomize execution the a script?
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> > I don't happen to have random installed on my system, however jot is
>=20
> It's in /usr/games/random of FreeBSD 4.8.
>=20
> > Won't randomNumber=3D$? Just return 0 if the previous command=20
> completes
> > successfully?
> > Shouldn't it be:
> > randomNumber=3D`random -e 60`
>=20
> No. In 'man 6 random', it says:
>=20
>      random [-er] [-f filename] [denominator]
>=20
>      -e      If the -e option is specified, random does not=20
> read or write any-
>              thing, and simply exits with a random exit value of 0 to
>              denominator - 1, inclusive.
>=20
> So you must capture its exit value for the random number :).

Good enough!  Thanks for the info!  :)