Date: Thu, 14 Mar 2002 22:33:26 +0100 From: Cliff Sarginson <csfbsd@raggedclown.net> To: freebsd-questions@freebsd.org, freebsd-ports@freebsd.org Subject: Re: make's default actions Message-ID: <20020314213325.GA11996@raggedclown.net> In-Reply-To: <20020314212733.GA11936@raggedclown.net> References: <20020314212239.97536.qmail@web14703.mail.yahoo.com> <20020314212733.GA11936@raggedclown.net>
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On Thu, Mar 14, 2002 at 10:27:33PM +0100, Cliff Sarginson wrote:
> On Thu, Mar 14, 2002 at 01:22:39PM -0800, Wayne Lubin wrote:
> > Hi,
> >
> > If you read the porters handbook it states that when
> > someone types "make" into a port directory make will
> > go in order to the following targets:
> >
> > fetch, extract, patch, configure, build
> >
> > This is refered to as make's default action. My
> > question is how is this acheived? Does freebsd use
> > some hached version of make? This clearly is not
> > standard actions for the make utility. If I wanted to
> > do a software project of my own on freebsd not related
> > to the port collection or porting at all for that
> > matter, and wanted to use the make utility, would the
> > make program still go through this default action, and
> > if so, how do I turn it off. Thanks for your help.
> >
> Make is a general purpose tool.
> I doubt the ports use a hacked version of it.
> The above actions are presumably a consequence of a standard port
> configuration makefile.
> What make does is determined by the actions you give it in a "makefile".
> It has a *lot* of intelligence built into it, but not at that level.
>
A thought, to demonstrate the above:
A "C" program, call it "foo.c"
main()
{
}
Type:
% make foo
You will now have an executable (albeit useless) program called foo.
You don't even need a makefile :)
--
Regards
Cliff Sarginson -- <csfbsd@raggedclown.net>
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