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Date: Wed, 29 Mar 2006 14:16:16 -0600
From: Dan Nelson <dnelson@allantgroup.com>
To: usleepless@gmail.com
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Cc: freebsd-questions@freebsd.org, Bill Moran <wmoran@collaborativefusion.com>
Subject: Re: Shell ( csh, sh ) scripting and seq-command
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In the last episode (Mar 29), usleepless@gmail.com said:
> > You
> > should be able to write a shell script
> 
> as i stated in my message, i lack shell scripting experience.
> 
> > that wraps jot and provides
> > its functionality in the same format as seq.
> 
> yes, and to convert steps to reps you will need $reps = ($end -
> $start) / $steps, and then see the difference between your script and
> the output of an actual linux seq.
> 
> for example:
>    seq 1 2 60 gives 1..3..5..7..59 ( see also my php and csh implementations )
> 
> a seq equivalent ( 3 par version ) would be:
> 
> @ reps = ( $3 - $1 ) / $2
> jot $reps $1 $3
> 
> which will give 1..3..5..7..9..12(!)..zzzz..60
>
> so how would your implementation of seq by using jot look like?

jot - $1 $3 $2

( which in your case would be "jot - 1 60 2" )

-- 
	Dan Nelson
	dnelson@allantgroup.com