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Date: Mon, 14 Apr 2003 04:49:13 -0700
From: David Schultz <das@freebsd.org>
To: "Andrey A. Chernov" <ache@nagual.pp.ru>
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	Christoph Kukulies <kuku@physik.rwth-aachen.de>,
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References: <200304141005.h3EA5GM01835@accms33.physik.rwth-aachen.de>
	<20030414101152.GA29163@nagual.pp.ru> <20030414102446.GA37148@nagual.pp.ru>
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cc: Christoph Kukulies <kuku@physik.rwth-aachen.de>
cc: freebsd-current@freebsd.org
Subject: Re: df displays 0.
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On Mon, Apr 14, 2003, Andrey A. Chernov wrote:
> On Mon, Apr 14, 2003 at 14:11:52 +0400, Andrey A. Chernov wrote:
> > On Mon, Apr 14, 2003 at 12:05:16 +0200, Christoph Kukulies wrote:
> > 
> > > /dev/ad0s1e    257838       22   237190    0.%    /tmp
> > 
> > Looks like new printf error.
> 
> Test program:
> 
> main() {
> (void)printf(" %5.0f%%\n", (double)0.1);
> }

I just took care of this.  The problem arises from a slight
inconsistency[1] in dtoa's handling of a precision of 0 (and a
corresponding bug in my code).  Specifically, if you tell it to
print 0.0 or any number >0.5 and <10 using precision 0 in the
mode used for %f, it will tell you that the decimal point comes
after the first digit by setting expt to 1.  But for numbers >0
and <=0.5, it sets expt to 0 instead.  (I think the rationale is
that in the latter cases, the leading digit isn't significant.)