Date: Thu, 22 May 2003 15:41:26 -0700 From: Joshua Oreman <oremanj@webserver.get-linux.org> To: Chuck Swiger <cswiger@mac.com> Cc: questions@freebsd.org Subject: Re: Zombie Process Message-ID: <20030522224126.GB17789@webserver.get-linux.org> In-Reply-To: <3ECCFDCF.4020103@mac.com> References: <4306.192.168.1.155.1053612014.squirrel@vipersystems.biz> <3ECCFDCF.4020103@mac.com>
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On Thu, May 22, 2003 at 12:41:51PM -0400 or thereabouts, Chuck Swiger seemed to write:
> Jason Lieurance wrote:
> [ ... ]
>
> Zombie processes are mostly harmless: they are a process which has
> finished and is sticking around because their parent hasn't reaped their
> exit status. Have the parent process do a wait()...
NOTE: This email is intended for if you really, truly, want to get rid
of those zombies. These procedures are untested, but they should
work :-)
Do `ps ax` and find the PID of the child. Then this:
$ ps axo ppid -p <the-pid-of-the-child> | grep -v PPID | sed 's/ //g'
It will show the PID of the parent. From now on, this will be referred
to as the-ppid. Now:
$ which `ps axo command -p <the-ppid> | grep -v COMMAND | cut -d' ' -f1`
It will give you the program - if not, try and find it yourself. This
will be called /path/to/the/program. The PID of the child will be called
the-pid. Now `debug' the parent program and call wait():
$ gdb /path/to/the/program the-ppid
[...]
(gdb) call wait(the-pid)
If it takes very long here, hit ^C.
(gdb) quit
The program is running. Quit anyway (and detach it)? yes
$ kill -CONT the-ppid
The zombie should've disappeared if you didn't have to press ^C; if you
did, just don't worry about it.
HTH,
-- Josh
>
> -Chuck
>
>
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