Date: Fri, 29 Jun 2001 10:54:38 +0400 From: Dmitriy Kyrhlarov <dimma@electromir.ru> To: Dave Tweten <tweten@nas.nasa.gov> Cc: Pete Fritchman <petef@databits.net>, freebsd-doc@FreeBSD.ORG Subject: Re: Fw: Re: Bourne Shell Syntax Wierdness Message-ID: <3B3C262E.B44B479D@electromir.ru> References: <8389E4C083FF6622C3256A7A0019EB8A.0019EBE9C3256A7A@electromir.ru>
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Hi! 1. sorry for my english. :-) Dave Tweten wrote: > > petef@databits.net said: > >you first take 'true || true' -- you end up with true. > > According to the man page, "||" is NOT "or". Instead it is an operator > that > causes the command to its right to be executed only if the simple command > to > its left fails. Therefore, 'true || true' means "continue without > executing > the rightmost "true". I can't understand where is a problem? true || true && echo "oops!" prints "oops!" true || echo "not oops!" && echo "oops!" prints "oops!" i.e. true || command 1 && command 2 equivalent: true && command 2 and it's a right... > command1 [ || command2 ] ... > command1 [ && command2 ] ... > Curiously, POSIX says nothing about a list containing both operators. pay attantion: "||" and "&&" -- part of command2, therefore true [ || command1 ] [ && command2 ] we can write: true [ && command2 ] By. Dmitriy To Unsubscribe: send mail to majordomo@FreeBSD.org with "unsubscribe freebsd-doc" in the body of the message
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