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Date:      Thu, 10 May 2001 13:25:51 -0400 (EDT)
From:      Dru <genisis@istar.ca>
To:        Wayne Pascoe <wayne.pascoe@realtime.co.uk>
Cc:        freebsd-questions@FreeBSD.ORG
Subject:   Re: OT: TCP/IP Subnetting
Message-ID:  <Pine.BSF.4.21.0105101324440.33793-100000@istar.ca>
In-Reply-To: <86r8xxnncd.fsf@pan.penguinpowered.org.uk>

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Hi Wayne,

What's your ultimate goal here? I see that you want to have 4 addresses on
one subnet, how many do you need on your other subnet and do they have to
all be on the same subnet? i.e. do you absolutely need 120 addresses on
one segment?

Dru


On 10 May 2001, Wayne Pascoe wrote:

> Hi all,
> 
> I have a /25 IP range that I need to subnet. I need to give 4
> addresses to one network and the remaining addresses to the other
> network.
> 
> So far, here are my workings:
> 
> Original Range:
> Network Address: 192.168.1.128
> Broadcast Address: 192.168.1.255
> Subnet Mask: 255.255.255.128
> Range: 192.168.1.129 - 192.168.1.254 (126 Addresses)
> 
> 4 Address Range:
> Network Address: 192.168.1.128
> Broadcast Address: 192.168.1.133
> Subnet Mask: 255.255.255.255.252
> Range: 192.168.1.129 - 192.168.1.132 (4 Addresses)
> 
> 120 Address Range:
> Network Address: 192.168.1.134
> Broadcast Address: 192.168.1.255
> Subnet Mask: 255.255.255. ???? 
> Range: 192.168.1.135 - 192.168.1.254 (120 Addresses)
> 
> Can anyone see what I am doing wrong here? I really can't work out the
> subnet mask for the 120 Address range. I need it to be that 
> 192.168.1.132
> and 
> 192.168.1.135 
> are on separate networks.
> 
> Sorry for the OT'ness, but I figure someone on the list is bound to
> know!
> 
> Thanks,
> 
> -- 
> - Wayne Pascoe 
> E-mail: wayne.pascoe@realtime.co.uk
> Phone : +44 (0) 20 7544 4668
> Mobile: +44 (0) 788 431 1675
> 
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> 
> 
> 
> 


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