Date: Thu, 28 Jun 2001 11:00:19 -0700 From: ChildsC@bcrail.com To: rmasse@mastery.ca, freebsd-questions@FreeBSD.ORG Subject: RE: awk help Message-ID: <01Jun28.105835pdt.119047@gatekeeper.bcrail.com>
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How about:
awk -F: '$3 > 1001 && $3 < 65500 { print $0 }' /etc/passwd > /var/db/user.db
Chris
-----Original Message-----
From: Ryan Masse [mailto:rmasse@mastery.ca]
Sent: Thursday, June 28, 2001 10:48 AM
To: FreeBSD-Questions
Subject: OT: awk help
i'm not to fimiliar with awk but i want to rip through /etc/passwd and print
out to file all users greater than uid 1001 and less than 65500. I've come
up with this so far;
awk -F: '$3 > 1001 { print $1 }' /etc/passwd > /var/db/user.db
i can't seem to create a statement that will printout both the lbount and
ubound of 1001 and 65500
can someone lend me their thinking cap?
Ryan
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