From owner-freebsd-current Sun Nov 1 19:43:15 1998 Return-Path: Received: (from majordom@localhost) by hub.freebsd.org (8.8.8/8.8.8) id TAA24429 for freebsd-current-outgoing; Sun, 1 Nov 1998 19:43:15 -0800 (PST) (envelope-from owner-freebsd-current@FreeBSD.ORG) Received: from rip.psg.com (rip.psg.com [147.28.0.39]) by hub.freebsd.org (8.8.8/8.8.8) with ESMTP id TAA24421 for ; Sun, 1 Nov 1998 19:43:11 -0800 (PST) (envelope-from randy@psg.com) Received: from localhost (651 bytes) by rip.psg.com via sendmail with P:stdio/R:inet_resolve/T:smtp (sender: ) (ident using unix) id for ; Sun, 1 Nov 1998 19:43:05 -0800 (PST) (Smail-3.2.0.101 1997-Dec-17 #1 built 1998-Oct-13) Message-Id: Date: Sun, 1 Nov 1998 19:43:05 -0800 (PST) From: Randy Bush MIME-Version: 1.0 Content-Type: text/plain; charset=us-ascii Content-Transfer-Encoding: 7bit To: freebsd-current@FreeBSD.ORG Subject: kerberos rlogin requires auth.conf Sender: owner-freebsd-current@FreeBSD.ORG Precedence: bulk X-Loop: FreeBSD.ORG in kerberized rlogin there is the following fragment: k = auth_getval("auth_list"); if (k && !strstr(k, "kerberos")) use_kerberos = 0; this means that, for me to do a kerberos login from A to B, that A must have auth_list = .* kerberos in /etc/auth.conf i thought that auth.conf controlled how folk get access TO the system, not from it. randy To Unsubscribe: send mail to majordomo@FreeBSD.org with "unsubscribe freebsd-current" in the body of the message