Date: Fri, 30 Sep 2005 19:30:27 +0100 From: Rob Pitt <rob@motionpath.com> To: freebsd-questions@freebsd.org Subject: Re: Simple PAM authentication code? Message-ID: <6E00FF16-452F-4710-A9B7-C5BC3DFA476D@motionpath.com> In-Reply-To: <200509301746.j8UHkh6x038676@spoon.beta.com> References: <200509301746.j8UHkh6x038676@spoon.beta.com>
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This is mostly taken from Linux Standards Base. Compile with -lpam -
lpam_misc.
HTH
- RP
#include <security/pam_appl.h>
#include <security/pam_misc.h>
#include <stdio.h>
int main(int argc, char *argv[])
{
static struct pam_conv conv;
conv.conv = misc_conv;
conv.appdata_ptr = NULL;
pam_handle_t *pamh;
int pam_status;
char *user;
pam_status = pam_start("testing", NULL, &conv, &pamh);
if (pam_status == PAM_SUCCESS)
pam_status = pam_authenticate(pamh, 0);
if (pam_status == PAM_SUCCESS) {
pam_get_item(pamh, PAM_USER, (const void **)&user);
fprintf(stdout, "Greetings %s\n", user);
} else {
printf("%s\n", pam_strerror(pamh, pam_status));
}
pam_end(pamh, pam_status);
}
On 30 Sep 2005, at 18:46, Brian J. McGovern wrote:
> Could someone point me at a short, straight forward bit of code that
> validates a given username and password via PAM? I've tried writing
> a short
> app to make sure PAM is working the way I want to locally, but no
> matter how
> good the info, I'm getting an authentication denied, so I know I'm
> missing something.
>
> The openpam site didn't seem to helpful documentation wise, and my
> connection to
> download the source seems to be timing out at the moment...
>
> -B
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