Date: Wed, 23 Feb 2005 22:41:32 -0500 From: Mark Frank <mark@mark-and-erika.com> To: David Bear <David.Bear@asu.edu> Cc: freebsd-questions@freebsd.org Subject: Re: awk print Message-ID: <20050224034132.GE3123@guinness.local.mark-and-erika.com> In-Reply-To: <20050224023605.GD31005@asu.edu> References: <20050223214010.GA31005@asu.edu> <20050223221926.GB69249@slackbox.xs4all.nl> <20050224023605.GD31005@asu.edu>
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* On Wed, Feb 23, 2005 at 07:36:05PM -0700 David Bear wrote:
> On Wed, Feb 23, 2005 at 11:19:26PM +0100, Roland Smith wrote:
> > On Wed, Feb 23, 2005 at 02:40:10PM -0700, David Bear wrote:
> > > I'm using awk to parse a directory listing. I was hoping there is a
> > > way to tell awk to print from $2 - to the end of the columns
> > > available.
> > >
> > > find ./ -name '*stuff' | awk '{FS="/" print $3---'}
> >
> > Is this what you mean?:
> >
> > find ./ -name '*stuff'|sed 's|\.[^/]*/[^/]*/||g'
>
> thanks for the advice. No, this doesn't do what I want.
>
> If I have a directory path /stuff/stuff/more/stuff/more/and/more
> that is n-levels deep, I want to be able to cut off the first two
> levels and print the from 2 to the Nth level.
So how about cut?
find ./ -name '*stuff'| cut -d/ -f4-
Mark
--
"The fix is only temporary...unless it works." - Red Green
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