Date: Fri, 13 Oct 2000 13:55:10 -0700 From: Sriranga Veeraraghavan <ranga@CSUA.Berkeley.EDU> To: Johan Pettersson <pettersson.johan@spray.se> Cc: freebsd-questions@FreeBSD.ORG Subject: Re: execv Message-ID: <200010132055.NAA17861@soda.csua.Berkeley.edu> In-Reply-To: Your message of "Fri, 13 Oct 2000 11:01:46 %2B0200." <Pine.BSF.4.21.0010131054320.84056-100000@ng4L117.i.spray.se\000>
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> I have problem with a C-program.
>
> -----8<------------------------
> char *arglist[] = { "-e pine" };
> .
> .
> execv("/usr/X11R6/bin/xterm", arglist);
> -----8<------------------------
>
> The function replaces the process image
> with xterm. But how do I pass arguments
> to xterm. (above doesn't work =(
Hi,
The man page sums it up pretty clearly. Here are the relavent parts:
int execv(const char *path, char *const argv[])
The initial argument for this functions is the pathname of a file
which is to be executed.
The second argument provides an array of pointers to null-terminated
strings that represent the argument list available to the new program.
The first element of the array of pointers, by convention, should
point to the file name associated with the file begin executed. The
array of pointers must be terminated by a NULL pointer.
You probably want to do something like:
char *arglist[] = { "/usr/X11R6/bin/xterm",
"-e",
"pine",
NULL };
...
execv (arglist[0],arglist);
HTH,
----ranga
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