Date: Sat, 20 Mar 1999 15:28:00 +0530 From: Samit Pal <samit@usa.ltindia.com> To: FreeBSD-Questions@FreeBSD.ORG Subject: rfork() Message-ID: <36F37127.7C0B121D@usa.ltindia.com>
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Can any one suggest how to use rfork( RFPROC | RFMEM );
according to the manual, freeBSD supports this and it should create a
new process
which will share the address space.
But what I'm getting is
a) It returns only to the parent process with a childID.
b) It doesn't go into child part
c) 'PS' shows that a child process is active.
Code:
#include <unistd.h>
main()
{
int childId;
printf("Parent Process start \n");
if ( (childId = rfork(RFMEM | RFPROC) ) == 0 ) {
printf("In Child childId(%d) PId(%d)\n",
childId,getpid() );
sleep(4);
exit(0);
}
{
char buf[10] = "Samit";
int nRet;
printf("Parent process continues with childId(%d)
%s,PID(%d)\n",
childId, buf,getpid());
sleep(5);
}
}
Output:
$ cc test.c
$ a.out &
$ Parent Process start
Parent process continues with childId(10759) Samit,PID(10758)
ps
PID TT STAT TIME COMMAND
10697 p2 Ss 0:00.07 -sh (sh)
10758 p2 S 0:00.00 a.out
10759 p2 Z 0:00.00 (a.out)
10760 p2 R+ 0:00.00 ps
why it is created zombie and it does not execute the code ?
--Samit.
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